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If the dimensions of a physical quantit...

If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`, then the physical quantity will be :

A

pressure if a =1 , b=-1, c =-2

B

velocity if a =1, b = 0 , c=-1

C

acceleration if a=0, b = -1, c=-2

D

for if a =0, b =-1, c =-2

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The correct Answer is:
A
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NARAYNA-UNITS AND MEASUREMENTS-EXERCISE-III
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