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If force (F) velocity (V) and time (T) a...

If force `(F)` velocity `(V)` and time `(T)` are taken as fundamental units, then the dimensions of mass are

A

`[FVT^(-1)]`

B

`[FVT^(-2)]`

C

`[FV^(-1)T^(-1)]`

D

`[FV^(-1)T]`

Text Solution

Verified by Experts

The correct Answer is:
D
`m= F^a Y^b T^c`
`M^1 L^0 T^0 = (MLT^(-2))^a (LT^(-1))^b. T^c`
`implies a=1,b=-1 and c=1 `
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