A student performs an experiment for determination of ` g [ = ( 4 pi^(2) L)/(T^(2)) ] , L ~~ 1m` , and he commits an error of `Delta L`. For `T` he takes the time of `n` oscillations with the stop watch of least count ` Delta T` . For which of the following data , the measurement of `g` will be most accurate ?

Options

A. `DeltaL = 0.5, DeltaT = 0.1, n =20`
B. `DeltaL = 0.5, DeltaT = 0.1, n = 50`
C. `DeltaL = 0.5, DeltaT = 0.01, n=20`
D. `DeltaL=0.5, DeltaT=0.05, n=50`

Answer

D

Explanation

`(Deltag)/(g) = (Deltal)/l + 2(DeltaT)/(T) ( Delta l and Delta T ` are least, and the number of reading are maximum`)`