When a current of (2.5 +- 0.5) ampere fl...

When a current of `(2.5 +- 0.5)` ampere flows through a wire, it develops a potential difference of `(20 +- 1)` volt, the resistance of the wire is

`(8pm2)sigma`

`(10pm3)sigma`

`(18pm4)sigma`

`(20pm6)sigma`

Text Solution

Verified by Experts

The correct Answer is:

`R pm Delta R = V/I + [ (DeltaV)/(V) + (DeltaI)/I ] R`

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