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Measure of two quantites along with the ...

Measure of two quantites along with the precision of respective measuring instrument is `A = 2.5 ms^(-1) +- 0.5 ms^(-1)`
`B = 0.10 s +- 0.01s` The value of AB will be

A

`(0.25 pm 0.08)m`

B

`(0.25 pm 0.5) m`

C

`(0.25 pm 0.05)m`

D

`(0.25 pm 0.135) m`

Text Solution

Verified by Experts

The correct Answer is:
A
Given A=2.5 `ms^(-1) pm 0.5 ms^(-1)`,
`B= 0.10 s pm 0.01 s`
`x = AB = (2.5)(0.10) = 2.25 m`
`(Deltax)/(x) = (DeltaA)/(A) + (DeltaB)/B`
`=(0.5)/(2.5) +(0.01)/(0.10)=(0.05+ 0.025)/(0.5) = (0.075)/(0.25)`
`Deltax = 0.075` = 0.08 m rounding off to two significant figures .
`AB=(0.25 pm 0.08)m`
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