Photon is quantum of radiation with energy E =hv where v is frequency and h is Planck's constant. The dimensions of h are the same as that of

Options

A. Linear impulse
B. Angular impulse
C. Linear momentum
D. Angular momentum

Answer

B, D

Explanation

We know that energy of radiation , E= hv
`[h] = ([E])/([V]) = ([ML^2 T^(-2)])/([T]^(=1))=[ML^2 T^(-1)]`
Dimension of linear impulse = Dimension of momentum `=[MLT^(-1)]`
As we known that linear impulse J=` DeltaP`
`implies ` Angular impulse `= tau dt = DeltaL ` = change in angular momentum
Hence, dimension of angular impulse
= Dimension of angular momentum
`=[ML^2 T^(1)]`
This is similar to the dimension of Planck.s constant h.