Statement-1:Electromotive force is expressed in newton.
Statement-2:Electric intensity is expressed in `NC^(-1)`

Options

A. Statement-1 is true and statement -2 is true
B. Statement -1 is true and statement-2 is false
C. Statement-1 is false and statement -2 is true
D. Statement-1 is false and statement -2 is false

Answer

To analyze the statements given in the question, we will evaluate each statement separately.

### Step 1: Evaluate Statement-1
The first statement claims that "Electromotive force is expressed in newton."

1. **Understanding Electromotive Force (EMF)**:
- EMF is a measure of the energy provided by a source of electric energy per unit charge. It is often generated by electrochemical cells or by changing magnetic fields.
- The unit of EMF is volts (V), not newtons (N).

2. **Conclusion for Statement-1**:
- Since EMF is measured in volts and not in newtons, Statement-1 is **incorrect**.

### Step 2: Evaluate Statement-2
The second statement claims that "Electric intensity is expressed in `NC^(-1)`."

1. **Understanding Electric Field Intensity**:
- Electric field intensity (E) at a point in an electric field is defined as the force (F) experienced by a unit positive charge (Q) placed at that point.
- Mathematically, it is expressed as:
\[ E = \frac{F}{Q} \]
- The unit of force (F) is newton (N) and the unit of charge (Q) is coulomb (C). Therefore, the unit of electric field intensity is:
\[ E = \frac{N}{C} \]
- This confirms that electric field intensity is indeed expressed in `NC^(-1)`.

2. **Conclusion for Statement-2**:
- Since electric field intensity is correctly expressed in `NC^(-1)`, Statement-2 is **correct**.

### Final Conclusion
- Statement-1 is incorrect, and Statement-2 is correct. Therefore, the overall evaluation leads us to conclude that the answer is that Statement-1 is false and Statement-2 is true.

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