Home
Class 11
PHYSICS
In a car race, A takes a time of t s, le...

In a car race, `A` takes a time of `t` s, less than car `B` at the finish and passes the finishing point with a velocity `v` more than car `B`. Assuming that the cars start from rest and travel with constant accelerations `a_(1)` and `a_(2)`. Respectively, show that `v=sqrt(a_(1) a_(2)t)`.

Text Solution

Verified by Experts

The distance covered by both cars in same
Thus `s_(1) = s_(2) =s`
If the cars take time `t_(1) and t_(2)` for the race and their velocities at the end of race be `v_(1) and v_(2)`, then it is given that
`v_(1) - v_(2) = v and t_(2) - t_(1) =t`
Now, `(v)/(t) = (v_(1)-v_(2))/(t_(2)-t_(1))=(sqrt(2a_(1)s)-sqrt(2a_(2)s))/(sqrt((2a)/(a_(2)))-sqrt((1)/(a_(1))))`
`=(sqrt(a_(1))-sqrt(a_(2)))/(sqrt((1)/(a_(2)))-sqrt((1)/(a_(1))))" "therefore (v)/(t) = sqrt(a_(1)a_(2))`
Promotional Banner

Similar Questions

Explore conceptually related problems

In a car race, A takes a time of t s, less than car B at the finish and passes the finishin point with a velocity v more than car B . Assuming that the cars stat from rest and travel with constant accelerations a_(1) and a_(2) . Respectively, show that vsqrt(a_(1) a_(2)t) .

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars start from rest and travel with constant acceleration a_1 and a_2 respectively. Show that v=sqrt (a_1 a_2) t.

In a car race, car A takes 4 s less than can B at the finish and passes the finishing point with a velcity v more than the car B . Assumung that the cars start form restand travel with constant accleration a_(1)=4 m s^(-2) and a_(2) =1 m s^(-2) respectively, find the velocity of v in m s^(-1) .

In a car race car A takes t_(0) time less to finish than car B and pases the finishing point with a velocity v_(0) more than car B . The cars start from rest and travel with constant accelerations a_(1) and a_(2) . Then the ratio (v_(0))/(t_(0)) is equal to

In a car race, car A takes t_0 time less to finish than car B and passes the finishing point with a velocity v_0 more than car B . The cars start from rest and travel with constant accelerations a_1 and a_2 . Then the ratio (v_0)/(t_0) is equal to.

In a car race, car A takes time t less than car B and passes the finishing point with a velocity of 12m//s more than the velocity with which car B passes the finishing point. Assume that the cars A and B start from rest and travel with constant acceleration of 9 m//s^(2) and 4 m//s^(2) , respectively. If v_(A) and v_(B) be the velocities of cars A and B, respectively, then

In a car race, car P takes time t_(0) less than car Q and passes the finishing point with a speed v_(0) more than the speed with which xar Q passses the finishing point. Assume that both cars start from rest and trasvel with constant acceeleration alpha and beta . Find v_(0) .

Two cars A and B are at rest at the origin O. If A starts with a uniform velocity of 20 m// s and B starts in the same direction with a constant acceleration of 2 m//s^(2) , then the cars will meet after time