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A parachutist drops freely from an aerop...

A parachutist drops freely from an aeroplane for 10 seconds before the parachute opens out. Then he descends with a net retardation of `2 m//s^(2)`. His velocity when he reaches the ground is `8 m//s` find the height at which he gets out of the aeroplane?

Text Solution

Verified by Experts

Distance he falls before the parachute opens is
`S_(1) = (1)/(2)g xx 100 = 490m`
Then his velocity , u = gt = 98.0 m/s
retardation = `2m//s^(2)`
`v^(2) - u^(2) = 2as_(2) rArr S_(2) = 2385m`
Total distance S `= S_(1) + S_(2) = 2385 + 490`
2875 m (height of aeroplane)
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