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A body moves with a velocity of 3 m//s d...

A body moves with a velocity of `3 m//s` due east and then turns due north to travel with the same velocity. If the total time of travel is 6s. The acceleration of the body is

A

`sqrT(3)m//s^(2)` towards north west

B

`(1)/(sqrt(2))m//s^(2)` towards north west

C

`sqrt(2)m//s^(2)` towards north east

D

all the above

Text Solution

Verified by Experts

The correct Answer is:
B

`a = (v - u)/(t) , bar(v_(i)) = v_(1)hati, barv_(r) = v_(2)hatj`
`Deltabarv = barv_(f) = v_(2)hatj - v_(1)hati , tan theta = (v_(2))/(v_(1))`
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