A bus accelerates uniformly from rest and acquires a speed of 36kmph in 10s. The acceleration is

Options

A. `1m//s^(2)`
B. `2m//s^(2)`
C. `1//2m//s^(2)`
D. `3m//s^(2)`

Explanation

To find the acceleration of the bus, we can use the formula for acceleration in uniformly accelerated motion. The steps are as follows:

### Step 1: Identify the given values
- Initial velocity (u) = 0 m/s (the bus starts from rest)
- Final velocity (v) = 36 km/h
- Time (t) = 10 s

### Step 2: Convert the final velocity from km/h to m/s
To convert km/h to m/s, we use the conversion factor:
\[ 1 \text{ km/h} = \frac{5}{18} \text{ m/s} \]
Thus,
\[ v = 36 \text{ km/h} = 36 \times \frac{5}{18} \text{ m/s} \]
Calculating this gives:
\[ v = 36 \times \frac{5}{18} = 10 \text{ m/s} \]

### Step 3: Use the formula for acceleration
The formula for acceleration (a) when starting from rest is given by:
\[ a = \frac{v - u}{t} \]
Substituting the known values:
\[ a = \frac{10 \text{ m/s} - 0 \text{ m/s}}{10 \text{ s}} \]
This simplifies to:
\[ a = \frac{10 \text{ m/s}}{10 \text{ s}} = 1 \text{ m/s}^2 \]

### Final Answer
The acceleration of the bus is \( 1 \text{ m/s}^2 \).

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