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Two bodies begin to fall freely from the...

Two bodies begin to fall freely from the same height. The second one begins to fall `tau` s after the first. The time after which the `2^(nd)` body begins to fall, the distance between the bodies equals to `l`, is

A

`(l)/(g tau) + (tau)/(2)`

B

`(g tau)/(l) + tau`

C

`(tau)/(lg) + (2)/(tau)`

D

`(g)/(l tau) + (tau)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(1) = (gt^(2))/(2), H_(2) = (g(t-tau)^(2))/(2) , l = H_(1) - H_(2)`
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