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A train accelerating uniormly from rest ...

A train accelerating uniormly from rest attains a maximum speed of `40ms^(-1)` in `20s`. It travels at this speed for `20s` and is brought to rest with uniform retardation i further `40s`. What is the average velocity during this period?

A

80/3 `ms^(-1)`

B

25 `ms^(-1)`

C

40 `ms^(-1)`

D

30 `ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

av velocity ` = (S_(1) + S_(2) + S_(3))/(80)`
= 25 m/sec
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