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A body is thrown vertically up to reach ...

A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning (in seconds) is

A

`sqrt(2) t`

B

`(1 + (1)/(sqrt(2)))`

C

`(3t)/(2)`

D

`(t)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
`H = (1)/(2)gt^(2), (H)/(2) = (1)/(2) g(t.)^(2)`, find t. = ?
Total time = t + t.
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