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A ball is released from the top of a tow...

A ball is released from the top of a tower of height `H m`. After `2 s` is stopped and then instantaneously released. What will be its height after next `2 s`?.

A

H-5

B

H-10

C

H-20

D

H-40

Text Solution

Verified by Experts

The correct Answer is:
D

`h_(1) = (1)/(2)gt_(1)^(2)(t = 2sec) , h_(2) = (1)/(2)gt_(2)^(2)(t = 2 sec)`
`h^(1) = H - (h_(1) + h_(2))`
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