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Two stones are thrown vertically upwards...

Two stones are thrown vertically upwards with the same velocity of `49 m//s`. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

A

58.8 m

B

111.5 m

C

117.6

D

122.5 m

Text Solution

Verified by Experts

The correct Answer is:
B
`h = (u^(2))/(2g) - (gt^(2))/(8)`
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