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A ball is projected vertically upwards w...

A ball is projected vertically upwards with a velocity of `25ms^(-1)` from the bottom of a tower. A boy who is standing at the top of a tower is unable to catch the ball when it passes him in the upward direction. But the ball again reaches him after 3 sec when it is falling. Now the boy catches it then the height of the tower is `(g=10ms^(-2))`

A

5 m

B

10 m

C

15 m

D

20 m

Text Solution

Verified by Experts

The correct Answer is:
D
`t = (2v)/(g), v^(2) - u^(2) = 2gh`
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