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A stone projected vertically up from the...

A stone projected vertically up from the ground reaches a height `y` in its path at `t_(1)` seconds and after further `t_(2)` seconds reaches the ground. The height `y` is equal to

A

`(1)/(2)g(t_(1) + t_(2))`

B

`(1)/(2)g(t_(1) + t_(2))^(2)`

C

`(1)/(2)gt_(1)t_(2)`

D

`gt_(1)t_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`h = y = (1)/(2)gt_(1)t_(2)`
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