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A particle starts its motion from rest u...

A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.

A

1) `s_(2)=2s_(1)`

B

2) `s_(2)=3s_(1)`

C

3) `s_(2)=4s_(1)`

D

4) `s_(2)=s_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
If the particle is moving in a striaght line under the action of a constant force or under constant acceleration a
using `s= ut+(1)/(2)at^(2)`
Since the body starts from the rest u=0
Now `S_(1)= (1)/(2)a(10)^(2)`…….(i)
and `s_(2)= (1)/(2)a(200^(2)`......(ii)
Diving Eq 9i) and Eq(ii) we get
`(s_(1))/(S_(2)) =((10)^(2))/((20)^(2)RightarrowS_(2)=4s_(1)`
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