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A particle move a distance x in time t a...

A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is alphaortional to.

A

1) `("velocity")^(3//2)`

B

2) `("distance")^(2)`

C

3) `("distance")^(-2)`

D

4) `("velocity")^(2//3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Given distance `x=(1)/(x+5)`………(i)
Differentiating E.q (i) w.r.t to we get
Velocity `v_(2)(dx0/(dt) = (-1)/(t+5)^(2)`……(ii) Again , differentitating E.q(ii)
Comparing Eqs (ii) and (iii) we get (a)`alpha(v)^(3//2)`
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