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A body is moving with velocity 30 m//s t...

A body is moving with velocity `30 m//s` towards east. After `10 s` its velocity becomes `40 m//s` towards north. The average acceleration of the body is.

A

1) `7m//s^(2)`

B

2) `sqrt7m//s^(2)`

C

3) `5m//s^(2)`

D

4) `1m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Average accelearation = `("changeinvelocity")/("Totaltime")`

`vecv_(L) = 30hatim//sandvecv_(1) = 40hatjm//s`
`Deltavecv = vecv_(t) - vecv_(1)` = 40hatj-30hatim//s`
`|Deltavecv| = sqrt(30^(2) + 40^(2)) = sqrt(900 + 1600) = 50m//s`
`veca = (|vecv_(f) - vecv_(1)|)/(Deltat) = (sqrt(50))/(10) = 50ms^(-2)`
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