Home
Class 11
PHYSICS
A particle is thrown vertically upward. ...

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : -
`(g=10 m//s^2)`

A

1) 16 m

B

2) 10 m

C

3) 8 m

D

4)18 m

Text Solution

Verified by Experts

The correct Answer is:
B
It is given velocity at half the height is `10ms^(-1)`
By equation of motion , we have
`v^(2) =u^(2)-2gh`
Where n is final velocity , g is acceleration due to gravity and s is displacment
At maximum height n=0
`therefore v^(2)=2gs`
`Rightarrowh= (u^(2))/(2g)`
AT half the height
`Rightarrow h=(h)/(2)=(1)/(2)(u^(2))/(2g)`
Now `100-u^(2)=2xx(-g)xx(u^(2)/(4g)`
`Rightarrowu=sqrt200ms^(-1)`
Maximum height attained
`=(200)/(2xx10)=10m`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

A ball is thrown vertically upward with a velocity of 20 m/s. Calculate the maximum height attain by the ball.

A body is throw vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

(a) A ball is thrown vertically upward with speed 10 m//s and it returns to the ground with speed 8 m//s . Find the maximum height attained by the ball. (b) A ball is thrown vertically upward and if air resistance is half of weight of the ball, find the ratio of time of ascent and time of descent. (C) Two balls A and B (m_(A) = 2 m_(B) = 2 m) are thrown vertically upward. If air resistance is mg//2 , find ratio of maximum height attained by them.