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Two bodies of different masses m(a) and ...

Two bodies of different masses `m_(a)` and `m_(b)` are dropped from two different heights, viz, a and b. The ratio of time taken by the two to drop through these distance is:

A

`(a)/(b)`

B

`(a^(2))(b^(2)`

C

`sqrt(a)/(b)`

D

ab

Text Solution

Verified by Experts

The correct Answer is:
C
When a body falls freely then u= 0 and `S=(1)/(2)gt^(2)` or `salphat^(2)`. Hence for two bodies of masses `m_(1)` and `M_(2)` to fall freely from height a and b respectively .
[ Note here that time taken to fall freely is independent fo mass of the body ]
`a alphat_(1)^(2)`and `balphat_(2)^(2)`
or `(t_(1)^(2))/(t_(2)^(2)) = (a)/(b)` or `(t_(1)/(t_(2)=sqrt(a)/(b)`
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