Home
Class 11
PHYSICS
The displacement y (in metre) of a body ...

The displacement y (in metre) of a body varies with time t (in seconds) as `y = -(2)/(3)t^(2)16t+2`.  The body comes to rest in a time 

A

8s

B

10s

C

12s

D

14s

Text Solution

Verified by Experts

The correct Answer is:
C

According to the queation `y = -(2)/(3)t^(2)+ 16t+2`
Compare it with standard equation: `X= ut+(1)/(2)at^(2)`
We have : `u=16ms^(-1), (a)/(2)=-(2)/(3)` or
`a=-(4)/(3)ms^(-2)` for a body to come to rest , V = 0 Using above values in V = u at we get
`0=16+(-(4)/(3))t` or t =12sec
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement y (in metres) of a body varies with time t ( in seconds ) as y= (-2)/(3) t^(2)+16t-12 . How long does the body take to come to rest ?

The displacement x of a body varies with time t as x= -2/3 t^(2)+16 t+2 . The body will come to rest after :

If S=6t^(2)-t^(3) , then the body comes to rest after time t=

At t=0 , a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x=-(2//3)t^2+16t+2 . Find the initial velocity of the body and also find how long does the body take to come to rest? What is the acceleration of the body when it comes to rest?

If displacements of a particle varies with time t as s = 1/t^(2) , then.

A body is projected at time t = 0 from a certain point on a planet's surface with a certain velocity at a certain angle with the planet's surface (assumed horizontal). The horizontal and vertical displacement x and y (in metre) respectively vary with time t in second as, x= (10sqrt(3)) t and y= 10t - t^2 . The maximum height attained by the body is

A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacements x and y (in meters) respectively vary with time t (in second) as x= 10 sqrt3t , y= 10t -t^2 What is the magnitude and direction of the velocity with which the body is projected ?

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

The magnitude of force (in Newtons) acting on a body varies with time (in micro second) as shown in the figure. The magnitude of total impulse of the force on the body from t = 4μs to t = 16μs is –