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A car, starting from rest, accelerates a...

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A

S = ft

B

`S = (1)/(6) ft^(2)`

C

` S = (1)/(72) ft^(2)`

D

`S = (1)/(4) ft^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`V^(2)-o^(2)=2Fs
`O^(2)-V^(2)=-2(f)/(2)._S_(3)}circleR S_(3)=2S`
`therefore S_(2)12S,`12s=vt also `V= sqrt2fs`
`therefore 12s= sqrt2fs.t, 144s^(2)= 2fs.t,S=(1)/(72)ft^(2)`
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