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A parachutist after bailing out falls fo...

A parachutist after bailing out falls for 10 s without friction. When the parachute opens he descends with an acceleration of `2 m//s^(2)` against his direction and reached the ground with `4 m//s` from what height he has dropped himself? `(g=10 m//s^(2))`

A

500m

B

2496m

C

2996m

D

4296m

Text Solution

Verified by Experts

The correct Answer is:
C
`S_(1)= (1)/(2)gt^(2), v= gt, v_(1)^(2)- V^(2)= 2as_(2), S= S_(1)+S_(2)`
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