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The velocity of a particle is v = v0 + g...

The velocity of a particle is `v = v_0 + g t + ft^2`. If its position is `x = 0` at `t = 0`, then its displacement after unit time `(t = 1)` is.

A

`V_(0) + 2g+ 3f`

B

`V_(0)+ (g)/(2)+ (f)/(3)`

C

`V_(0)+g +f`

D

`V_(0)+(g)/(2)+f`

Text Solution

Verified by Experts

The correct Answer is:
B
Given velocity of particle , `V= V_(0)= gt+ ft^(2)`
`therefore displacement `S= intvdt`
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