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A particle of mass 0.1 kg is executing s...

A particle of mass 0.1 kg is executing simple harmonic motion of amplitude 0.1 m. When the particle passes through the mean position, its kinetic energy is `8xx 10^(-3) J`.
If the initial phase is `45^@` , the equation of its motion is (Assume, x(t) as the position of the particle at time t . )

A

`y = 0.1 sin (3T+(pi)/(4))`

B

`y = 0.1 sin (4T + (pi)/(3))`

C

`y = 0.1 sin (4T + (pi)/(4))`

D

`y = 0.4 sin (6T + (pi)/(4))`

Text Solution

Verified by Experts

The correct Answer is:
C
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