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The equation for the displacement of a p...

The equation for the displacement of a particle executing `SHM` is `x = 5sin (2pit)cm` Then the velocity at `3cm` from the mean position is( in cm//s)

A

`2 pi`

B

`3 pi`

C

`4 pi`

D

`8 pi`

Text Solution

Verified by Experts

The correct Answer is:
D
A = 5, `omega = 2 pi`
`v = omega sqrt(A^(2) - x^(2)) = (2pi) sqrt(5^(2) - 3^(2)) = 8 pi`
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NARAYNA-OSCILLATIONS-EXERCISE - I (H.W)
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  10. The acceleration of a particle in SHM is 0.8ms^(-2), when its displace...

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  11. A body of mass 0.5kg is performing SHM with a time period .^(pi)//(2) ...

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