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An object is attched to the bottom of a ...

An object is attched to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is `15cm//s` and the period is `628` milli seconds. The amplitude of the motion in centimetres is

A

`3.0`

B

`2.0`

C

1.5

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = A omega`
`15 = A xx (2pi)/(628 xx 10^(-3))`
A = 1.5 cm
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NARAYNA-OSCILLATIONS-EXERCISE - I (H.W)
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  2. The time period of oscillation of a particle that executes SHM is 1.2s...

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  5. The equation of motion of a particle in SHM is a +16 pi^(2)x = 0. Here...

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  6. A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum ...

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  7. The acceleration of a particle in SHM is 0.8ms^(-2), when its displace...

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  8. A body of mass 0.5kg is performing SHM with a time period .^(pi)//(2) ...

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  9. A body of mass 1//4 kg is in SHM and its displacement is given by the ...

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  10. Four simple harmonic vibrations x(1) = 8s "in" (omegat), x(2) = 6 si...

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  13. The velocities of a body executing SHM at displacement 'a' and 'b' are...

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  14. A block of 0.5kg is placed on a horizontal platform. The system is mak...

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  15. Due to some force F(1) a body oscillates with period 4//5s and due to ...

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  16. A simple pendulum performs simple harmonic motion about x=0 with an am...

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  17. particle is executing the motion x=A cos (omegat-theta) The maximum ve...

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  18. A particle executes simple harmonic motion with a period of 16s. At ti...

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  19. A particle executing simple harmonic motion with amplitude of 0.1 m. A...

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  20. A body is executing SHM. If the force acting on the body is 6N when th...

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