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A particle executing SHM is described by...

A particle executing SHM is described by the displacement function `x(t)=Acos(omegat+phi)`, if the initial (t=0) position of the particle is 1 cm, its initial velocity is `pii" cm "s^(-1)` and its angular frequency is `pis^(-1)`, then the amplitude of its motion is

A

`pi` cm

B

2 cm

C

`sqrt(2)` cm

D

1 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`x = A cos (omega t + phi) rArr 1 = A cos phi rArr cos phi = (1)/(A)`
`v =- A omega sin (omegat + phi) rArr pi = A(pi) sin phi rArr sin phi = (1)/(A)`
`phi = (pi)/(4) rArr A = sqrt(2)` cm
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