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A block of 0.5kg is placed on a horizont...

A block of `0.5kg` is placed on a horizontal platform. The system is making vertical oscillations about a fixed point with a frequency of `0.5 Hz`. The maximum displacement of oscillation, if the block does not lose contact with the horizontal platform is nearly

A

0.5 m

B

0.75 m

C

1 m

D

1.2 m

Text Solution

Verified by Experts

The correct Answer is:
C

`a_(max) lt g`
`omega^(2) A lt g`
`A lt (10)/((2pi (0.5))^(2)) = (10)/(pi^(2))1m`
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NARAYNA-OSCILLATIONS-EXERCISE - I (H.W)
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  2. The velocities of a body executing SHM at displacement 'a' and 'b' are...

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  3. A block of 0.5kg is placed on a horizontal platform. The system is mak...

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  7. A particle executes simple harmonic motion with a period of 16s. At ti...

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  8. A particle executing simple harmonic motion with amplitude of 0.1 m. A...

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  9. A body is executing SHM. If the force acting on the body is 6N when th...

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  10. A particle executes SHM on a straight line. At two positions, its velo...

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  11. A particle moves such that its acceleration is given by a =- beta (x-2...

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  12. The displacement of a particle executing S.H.M from its mean position ...

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  13. A particle is executing SHM with an amplitude of 2 m. The difference i...

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  14. A simple pendulum having a bob of mass 100 g is oscillating with a max...

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  16. A pendulum suspended from the roof of an elevator at rest has a time ...

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  17. A seconds pendulum is suspended from the roof of a lift. If the lift i...

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  18. If the length of a seconds pendulum is increased by 2% then in a day t...

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  19. Two simple pendulums have time periods T and 5T//4. They start vibrati...

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  20. Two simple pendulums of length 100m and 121m start swinging together. ...

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