A simple pendulum performs simple harmonic motion about `x=0` with an amplitude a ans time period T. The speed of the pendulum at `x = (a)/(2)` will be

Options

A. `(pi A sqrt(3))/(T)`
B. `(pi A)/(T)`
C. `(pi A sqrt(3))/(2T)`
D. `(3 pi^(2) A)/(T)`

Answer

C

Explanation

`v = (2pi)/(T) sqrt(A^(2) - ((A)/(2))^(2)) = (sqrt(3) pi A)/(T)`