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particle is executing the motion x=A cos...

particle is executing the motion `x=A cos (omegat-theta)` The maximum velocity of the particle is

A

`A omega cos theta`

B

`A omega`

C

`A omega sin theta`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
`x = A cos (omega t - theta) rArr v = - A omega sin (omega t - theta)`
`v_(max) = A omega`
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NARAYNA-OSCILLATIONS-EXERCISE - I (H.W)
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