If the length of a seconds pendulum is increased by `2%` then in a day the pendulum

Options

A. loses 764 s
B. loses 964 s
C. gains 764 s
D. loses 864 s

Answer

D

Explanation

`(Delta T)/(T) = (1)/(2). (Delta l)/(l) = (1)/(2) xx ((2)/(100)) = (1)/(100)`
`Delta T = (1)/(100) xx 86400 = 864s` (loses)