The amplitude of oscillation of particles in `SHM` is `sqrt(3)cm`. The displacement from mean position at which its potential and kinetic energies are in the ratio `1:2` is

Options

A. 1 cm
B. 0.866 cm
C. `(1)/(sqrt(3))` cm
D. `sqrt(2)` cm

Answer

A

Explanation

`(U)/(K) = (1)/(2)`
`((1)/(2) m omega^(2) x^(2))/((1)/(2) m omega^(2) (A^(2) - x^(2))) = (1)/(2) rArr x = (A)/(sqrt(3)) = (sqrt(3) cm)/(sqrt(3)) = 1 cm`