Find the average kinetic energy of a simple harmonic oscillator if its total energy is `10` joule and minimum potential energy is `2` joule.

Options

A. 1J
B. 4J
C. 8J
D. 5J

Answer

B

Explanation

E = 10
`U_(min) + K_(max) = 10`
`2 + K_(max) = 10 rArr K_(max) = 8`
`rArr (1)/(2) mA^(2) omega^(2) = 8`
`K_(avg) = (1)/(2) K_(max) = 4` J