The total energy of a particle executing simple harmonic motion is `16J`. What will be total energy of particle if amplitude is halved and frequency is doubled?

Options

A. 1J
B. 64J
C. 16J
D. 256J

Answer

C

Explanation

`E = (1)/(2) mA^(2) omega^(20 = 16` J
`E^(1) = (1)/(2) m ((A)/(2))^(2) (2 omega)^(2) = (1)/(2) m A^(2) omega^(2) = 16` J