The total mechanical energy of a harmonic oscillator of amplitude `1m` and force constant `200N//m` is `150J`. Then

Options

A. The minimum PE is zero
B. The maximum PE is 100 J
C. The minimum PE is 50 J
D. The maximum PE is 50 J

Answer

C

Explanation

`K_(max) = (1)/(2) A^(2) = (1)/(2) (200) (1)^(2) = 100 J`
`U_(min) = E - K_(max) = 50 J`
`K_(min) = 0 rArr U_(max) = E - K_(min) = 150 - 0 = 150 J`