The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9 J and its amplitude is 0.01 m, its time period would be

Options

A. `(pi)/(100)`
B. `(pi)/(50)`
C. `(pi)/(20)`
D. `(pi)/(10)`s

Answer

A

Explanation

At mean position, `U_(min) = 5J`
`K_(max) = E - U_(min) = 9 - 5 = 4J`
`(1)/(2) (2) (0.01)^(2) omega^(2) = 4 rArr omega = 200 rArr T = (2pi)/(200) = (pi)/(100)s`