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The amplitude of a damped oscillator bec...

The amplitude of a damped oscillator becomes `(1)/(27)^(th)` of its initial value after `6` minutes. Its amplitude after `2` minutes is

A

`(A_(0))/(3)`

B

`(A_(0))/(9)`

C

`(A_(0))/(54)`

D

`(A_(0))/(81)`

Text Solution

Verified by Experts

The correct Answer is:
A

`A = A_(0) e^(-vt)`
`(A_(0))/(27) = A_(0)e^(-v(6)) rArr e^(-6v) = (1)/(27)`
After 2 min, `A = A_(0)e^(-v(2))`
`A = (A_(0))/(3)`
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