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A simple pendulum with a brass bob has a...

A simple pendulum with a brass bob has a period `T`. The bob is now immersed in a nonviscous liquid and oscillated. If the density of the liquid is `1//8th` of brass, the time period of the same pendulum will be

A

`sqrt((8)/(7))T`

B

`(8)/(7)`T

C

`(64)/(49)`T

D

T

Text Solution

Verified by Experts

The correct Answer is:
A
`T^(1) = R sqrt((rho_(B))/(rho_(B) - (rho_(B))/(8))) = T sqrt((8)/(7))`
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