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Two pendulums have time period T and 5T/...

Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

A

`45^(@)`

B

`90^(@)`

C

`60^(@)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

When bigger pendulum of time period (5T/4) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second `= pi//2 rad = 90^(@)`.
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