Two simple harmonic motion of angular frequency `100and 1000 rads^(-1)` have the same displacement amplitude The ratio of their maximum acceleration is

Options

A. `1 : 10`
B. `1 : 10^(2)`
C. `1 : 10^(3)`
D. `1 : 10^(4)`

Answer

B

Explanation

Acceleration of simple harmonic motion is `a_(max) = - omega^(2) A`
or `((a_(max))_(1))/((a_(max))_(2)) = (omega_(1)^(2))/(omega_(2)^(2))` (As A remains same)
or `((a_(max))_(1))/((a_(max))_(2)) = ((100)^(2))/((1000)^(2)) = ((1)/(10))^(2) = 1 : 10^(2)`