A particle is executing a simple harmonic motion. Its maximum acceleration is `alpha` and maximum velocity is `beta`. Then, its time period of vibration will be

Options

A. `(2 pi beta)/(alpha)`
B. `(beta^(2))/(alpha^(2))`
C. `(alpha)/(beta)`
D. `(beta^(2))/(alpha)`

Answer

A

Explanation

In SHM `a_(max) = omega^(2) A`
and `v_(max) = omega A`
`therefore (alpha)/(beta) = omega" "therefore T = (2 pi beta)/(alpha)`
`therefore (1)` is the correct option