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A and B are two points on the path of a ...

A and B are two points on the path of a particle executing SHM in a straight line, at which its velocity is zero. Starting from a certain point X `(AXltBX)` the particle crosses this pint again at successive intervals of 2 seconds and 4 seconds with a speed of `5m//s`
Q. The ratio `(AX)/(BX)` is

A

`(sqrt(2))/(sqrt(2) + 1)`

B

`(sqrt(2) - 1)/(sqrt(2) + 1)`

C

`(sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`

D

`(sqrt(2) + 1)/(sqrt(2) - 1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`T = 4.8 sec, t = (1.2)/(2) = 0.6 sec = (T)/(8)`
`x =- (A)/(sqrt(2)), (AX)/(XB) = (A-|x|)/(A+|x|)`
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