Time period of a simple pendulum of length L is `T_(1)` and time period of a uniform rod of the same length L pivoted about an end and oscillating in a vertical plane is `T_(2)`. Amplitude of osciallations in both the cases is small. Then `T_(1)/T_(2)` is

Options

A. `sqrt((4)/(3))`
B. 1
C. `sqrt((3)/(2))`
D. `sqrt((2)/(3))`

Answer

C

Explanation

`T_(1) = 2pi sqrt((l)/(g))," "T_(2) = 2pi sqrt((I)/(Mgd))`
`I = (Ml^(2))/(3), d = (l)/(2)`