I toss three coins together. The possible outocmes are no heads, 1 head 2 head and 3 heads. So, I say that prbability of no heads is `(1)/(4)`. What is wrong with this conclusion?

A coin is tossed 3 times. List the possible outcomes. Find the probability of getting (i) all heads (ii) atleast 2 heads

A coin is tossed 3 times. List the possible outcomes. Find the probability of getting (i) all heads (ii) atleast 2 heads

A box contain three coins, one coin is fair, one coin is two-headed, and one coin is weighted so that the probability of heads, appearing is 1/3 . A coin is selected at random and tossed. Then the probability that heads appears is

A box contain three coins: one coin is fair, one coin is two-headed, and one coin is weighted so that the probability of heads, appearing is 1/3 . A coin is selected at random and tossed. Then the probability that heads appears is

Three coins tossed together. Find the probability of getting: i. Exactly two heads ii. At least to heads iii. At lest one head and one tail.

Three coins tossed together. Find the probability of getting: i. Exactly two heads ii. At least to heads iii. At lest one head and one tail.

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes: Outcome: 3 heads 2 heads 1 head No head Frequency: 23 72 77 28 Find the probability of getting: (i) three heads (ii) two heads and one tail (iii) at least two heads

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes: Outcome: 3 heads 2 heads 1 head No head Frequency: 23 72 77 28 Find the probability of getting: (i) three heads (ii) two heads and one tail (iii) at least two heads

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes: Outcome: 3 heads 2 heads 1 head No head Frequency: 23 72 77 28 Find the probability of getting: (i) three heads (ii) two heads and one tail (iii) at least two heads