Ratio of Consecutive Terms & coefficients .

The two consecutive terms whose coefficients in the expansion of (3 + 2x)^(94) are equal, are

Ratio Of Consecutive Terms In Binomial Expansion

If in the expansion of (1+x)^(n) the coefficient of three consecutive terms are 56,70 and 56, then find n and the position of the terms of these coefficients.

If in the expansion of (1+x)^n the coefficient of three consecutive terms are 56,70 and 56, then find n and the position of the terms of these coefficients.

The ratio of three consecutive binomial coefficients in the expansion of (1+x)^n is 2:5:12 . Find n.

Show that no three consecutive binomial coefficients can be in GP .

The ratio of three consecutive terms in expansion of (1+x)^(n+5) is 5:10:14 , then greatest coefficient is

If a,b and c are three consecutive coefficients terms in the expansion of (1+x)^(n), then find n.

If the three consecutive coefficients in the expansion of (1 + x)^n are in the ratio 1: 3 : 5, then the value of n is:

In the expansion of (1+x)^(20), if ratio of nth term coefficient and (n+1)^(th) term coefficient is 1:2, then find the value of n.