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A gas expands by 0.5L against a constant...

A gas expands by `0.5L` against a constant pressure of `1 atm`. Calculate the work done in joule and calorie.

Text Solution

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Work=`-P_(ect)xx`volume change
`=-1xx0.5=-0.5`litre-atm
`=-0.5xx101.328J=-50.664J`
`0.5"Litre"-atom=-0.5xx24.20cal=-12.10cal`
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